Energy of the Nokia N8 in free fall

edited January 2011 in Sciences
A Nokia N8 was dropped for free fall from a five storey building. If each storey and the ground floor is 3.5m tall each. What is the approximate energy (in Joules) of the Nokia N8 as it hits the ground? First correct answer (in our judgment) gets a N200 Glo Recharge PIN. Click Reply/Comment to answer. State all variables and constants used. No need to show all working. Editing after posting is no-longer allowed. So read your response carefully before posting. Result in 3 to 5 hours.<br /><br />Terms and conditions apply.
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Comments

  • The energy of the nokia N8 involved in a free fall is the potential energy of the nokia N8, which is derived by the formula mxgxh (mass x acceleration due to gravity x height).<br />The mass of the nokia N8 is 0.135 kg or 135 grams<br />the height is 21 m (3.5m x 5storeys plus ground floor )<br />acceleration due to gravity is 9.8m/second square<br />mxgxh= 0.135 x 21 x 9.8 = 27.783 joules
  • the mass of nokia N8 is 135g, acceleration due to gravity is 10, then height is h = 3.5 x 5= 17.5, mgh= 135x17.5x10=23625joules
  • Congratulations martinkem, your answer has been chosen as the first correct answer again. I will be sending you a N200 Glo Recharge PIN soon.
    The Truth is Out There.
  • The mass of nokia N8 = 0.135kg. The height of 5 storey building + ground floor = (5*3.5)+3.5=21m. Acceleration due to gravity(g)=10m/secondsquare. The energy of nokia N8= potential energy= mgh= 0.135*10*21= 28.350jouls 
  • Sorry i have no idea about this.
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